Jika f(x) = x+3, dan g(x) = x²-1, maka nilai (fog)^-1(1) adalah
Jawab:
fog(x)
= f(g(x))
= f(x²-1)
= x²-1+3
= x²+2
mencari invers ⇒ dibalik x & y
y = x²+2 ⇒ x = y²+2
x = y²+2
y² = x-2
y = √(x-2)
fog⁻¹(1) = √(1-2)
= √-1
Jawaban:
(fog)^-1(1) = -1
Penjelasan dan langkah-langkah:
(fog)(x) = (x² - 1) + 3
= x² - 1 + 3
= x² + 2
(fog)^-1(x) = x² - 2
(fog)^-1(1) = (1)² - 2 = 1 - 2 = -1
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